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Maleenhan

dua buah benda masing-masing muatannya +4 x 10min2076 dan +3 x 10min6C, terletak pada jarak 3cm. jika k = 9 x 102079 N m\xb2/C\xb2 maka besar gaya tolak kedua muatan tersebut adalah

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dua buah benda masing-masing muatannya +4 x 10min⁶ dan +3 x 10min6C, terletak pada jarak 3cm. jika k = 9 x 10⁹ N m²/C² maka besar gaya tolak kedua muatan tersebut adalah​

 

Jawaban:

120 N

Penjelasan:

Diketahui :

q1 = 4 \times {10}^{ - 6} \: c

q2 = 3 \times {10}^{ - 6} \: c

r = 3 \: cm = 3 \times {10}^{ - 2} \: m

k = 9 \times {10}^{9}

Ditanyakan :

Fc

Jawab :

fc = \frac{k \times q1 \times q2}{ {r}^{2} }

fc = \frac{9 \times {10}^{9} \times 4 \times {10}^{ - 6} \times 3 \times {10}^{ - 6} }{ {(3 \times {10}^{ - 2}) }^{2} }

fc = \frac{9 \times 12 \times {10}^{ - 3} }{9 \times {10}^{ - 4} }

fc = 12 \times {10}^{ - 3 + 4}

fc = 12 \times {10}^{1}

fc = 120


Maleenhan
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